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kairton
Posts: 2 Joined: 2009-05-28 06:33:07
Post
by kairton » 2009-05-28 06:44:50
I want a script that the end result to be like that appears in the first image, but I can only make it as the second image, can someone help me?
First Image
Second Image
I used the following code:
$$ITEM_BEGIN
<table>
<tr>
<td id='td1' align='center' valign='center' ><img src="$$ITEM_PICTUREFILENAME" width="95" height="135"></td>
</tr>
<tr>
<td id='td1' align='center' width='120'>$$ITEM_TRANSLATEDTITLE</td>
</tr>
</table>
$$ITEM_END
But I do not know anything about HTML, so it is difficult for me to make it.
Thanks.
antp
Site Admin
Posts: 9903 Joined: 2002-05-30 10:13:07
Location: Brussels
Post
by antp » 2009-05-28 13:11:21
With just HTML it will not be possible, but with some CSS it is rather easy.
Instead of using a table and tr/td tags, you have to use CSS to make images appear side by side.
Like what I did for imcdb galleries, e.g.
http://www.imcdb.org/movie_322259-2-Fast-2-Furious.html
Basically, each image+text is in a <div> tag, and this div is linked to a CSS style which as the "float" attribute.
But if you do not know much HTML this sounds maybe complicated...
kairton
Posts: 2 Joined: 2009-05-28 06:33:07
Post
by kairton » 2009-05-28 20:44:19
I did, of course, was well below the level of his, but with time I will study and will improve.
I used the following code:
<style type="text/css">
div.figure {
float: left;
width: 110;
height: 170;
margin: 0.5em;
padding: 0.5em;
}
div.figure p {
text-align: center;
font-style: bold;
font-size: smaller;
text-indent: 0;
}
</style>
$$ITEM_BEGIN
<div class="figure">
<p><img src="$$ITEM_PICTUREFILENAME" width="95" height="135">
<p>$$ITEM_TRANSLATEDTITLE
</div>
$$ITEM_END
Thank you for the tip to use the DIV, I would never do that without this trick.